Summing a progression and finding square roots geometrically
A rule for summing a series, and a compass construction giving the root of 9 as 3
The upper note gives a rule for summing an arithmetic progression: 8 multiplied by itself is 64, from which half is removed and half the multiplier added back, yielding 36 as the sum of the units from 1 to 8; a squared grid crossed by a diagonal illustrates it. A second, longer note beside a semicircle diagram teaches how to find any square root geometrically, worked here for the root of 9. The compass draws the semicircle d f e on the line d e, and the perpendicular raised at b meets the circle at a, so that a b is the root, checked against the 3-4-5 right triangle a b c. Both demonstrations are pure number and geometry, with no other subject on the sheet.
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Finding a square root by a semicircle construction
To find the root of 9, the value is laid on the line b e with one unit added to make the whole line d e; from its midpoint c the semicircle d f e is drawn, and the perpendicular at b meets the circle at a. The segment a b is then the root, verified against the right triangle a b c with sides 3, 4 and 5.
A rule for summing the progression 1 to 8
Eight times eight makes 64; removing half leaves 32 squares (28 whole and 8 halves), and adding another 8 halves gives 36. The same rule finds the sum of the units from 1 to 8: square 8, take half of the result, then add half the multiplier.
