Dividing a suspended weight between two cords by geometry
The perpendicular splits the force angle; loads in proportion to the triangles and bases
Leonardo shows how a hanging weight is shared between two cords by dropping the perpendicular that bisects the angle where the cords meet: the loads stand in the same proportion as the two divided angles, and as the two triangles and their bases. He notes that when this perpendicular cannot divide the angle, only one cord truly bears the weight and the other counts for nothing, and that the dividing perpendicular passes through the centre of gravity, splitting the load into two equal parts. He treats only natural weight, not force, which has no weight of its own. Pulley diagrams (4 5 1; 4 n 1, r, 3 4 1) and a labelled force triangle (a d e, c, f) accompany the argument.
On this page
Only natural weight is reckoned, not force
Here account is taken of natural weight and not of force, because force has no weight; the natural weight lies in the straight vertical hangings.
The perpendicular bisecting the angle divides the load
When two lines a c and e c descend from the horizontal a e to compose the angle c that suspends weight f, the perpendicular d c divides that angle into a c d and d c e. The cords then receive the weight in the same proportion as those two angles, and as the quantities of the two triangles.
When the perpendicular cannot divide the angle
When the perpendicular falling into the angle that supports the weight cannot divide that angle, it is a manifest sign that only one cord supports the weight and the other counts for nothing.
Pulleys carrying the divided load
A weight is carried on cords running over pulleys (labelled 4 5 1, and 4 n 1, r, 3 4 1). Such proportion is from weight to weight as from triangle to triangle, and from triangle to triangle as from base to base.
