Balances with friction: equilibrium on equal and unequal arms
'On simple equality'; weights on rollers, the friction quarter-rule, and the centre of gravity of a hanging cord
Under the heading 'On simple equality', both folios work through the equilibrium of balances loaded with weights hung from rollers, taking careful account of friction (confregazione). Leonardo repeatedly treats friction as one quarter of the load and computes the extra counterweight needed to keep equal arms in balance, with worked fractions such as 3/8 divided by 7 giving 3/56. He states a rule for scaling the friction with the length of the balance arm (dividing it into 3, 7, 11, 15 and 19 for equal, double, triple, quadruple and quintuple arms) and notes that the centre of a body hung by a single cord falls below the cord's central line. The sheet is crowded with pulley, roller and balance diagrams labelled with weights and fractions.
On this page
Balancing weights on equal arms with friction
Under 'On simple equality', a and g weigh 4 pounds (2 of the roller and 2 of the hung weight), giving one pound of friction marked at b. Leonardo shows that although the equal arms carry 3 pounds against 2, the 3 never wins because a further quarter (3/4) goes into friction, so an added pound is needed at e whose quarter, joined to 3/4, restores the balance.
Centre of gravity of a body on a single cord
Beside a figure, Leonardo states that the centre of gravity of any heavy body suspended by a single cord falls below the central line of that cord. He repeats that the centre of every suspended heavy body falls below the centre of the single cord that sustains it.
Working the friction fractions
In a case marked 'by 7', Leonardo divides 3/8 by 7 to get 3/56, takes this as the quarter of the friction, and clothing it obtains 12/56 for the added weight below. Adding the 3/56 to the 21/56 already found yields 24/56 of friction against 12/56 of weight.
Scaling friction with the length of the balance arm
Leonardo gives a general rule: because on an equal arm the 3/4 weight is divided into 3 parts, on a double arm the friction is divided into 7, on a triple into 11, quadruple 15 and quintuple 19. One of the fractions is always to be 'clothed' with its body by multiplying by 4, since a sub-quadruple part of the body goes into friction on the roller.
