Pyramids cut by parallel planes; triangle centres of gravity
Proportion of a truncated pyramid's sides, with geometric constructions and a pulley for weighing a sphere
This mount joins two rectos side by side. The upper leaf develops the geometry of pyramids cut by planes parallel to their base — the truncated portion always keeps the same proportion among its sides that the whole pyramid had — and repeatedly proves that a triangle's centre of gravity lies where its three medians intersect; a small marginal device shows a pulley applied to a sphere for weighing a portion of it without removal. The lower leaf gathers plane-geometry constructions: raising a right angle from the endpoint of a line by means of a semicircle, and a series of quadrature exercises that equate lettered figures (a b equal, c d equal, and so on). The manuscript bears much further dense mirror-script beyond the blocks transcribed here.
On this page
A truncated pyramid keeps the proportion of the whole
Pyramids cut by lines equidistant from their base always keep among their sides the same proportion the whole pyramid had among its entire sides. Leonardo restates the theorem several ways and adds that these sides never vary their proportion. A lettered proof takes the cut at e f and argues from the whole pyramid's base being half its axis.
A triangle's centre of gravity at the crossing of its medians
Every triangle has three medians, each dividing it into two equal parts, so each carries the centre of gravity of the whole triangle. Since the centre can be only one and in a single place, it must lie where the three medians intersect. Leonardo reduces 'three centres to one' by necessity.
A pulley for weighing a portion of a sphere
A marginal note beside a pulley applied to a sphere describes a way of weighing any portion of a sphere without removing it, and of learning what proportion that portion bears to the whole sphere. The surrounding text returns to the three medians and the single centre of gravity.
A right angle raised from the end of a line
Given the line a c, build the equilateral triangle a b c; with the same compass opening set the point at b and draw the semicircle c a d, then draw d a, and a will be a right angle. The construction is illustrated by a right triangle inscribed in a semicircle.
Quadrature exercises equating lettered figures
A run of small figures pairs curved and straight areas and marks them equal — a b equal, c d equal, e f equal, and o is squared. One note observes that the part f remains to be squared, as on the other side.
