Proof of the Counterweight Calculation for a Pivot's Friction
On checking whether the friction-and-counterweight computation is correct
Continuing the pivot-friction study, this sheet is headed 'on the proof, whether it is well calculated,' with balance diagrams in the margins. Leonardo gives two checks: dividing the friction by the number of parts of the counterweight arm should return the counterweight of that friction, and that result should stand in the same proportion to the friction as the friction arm to the counterweight arm. He dwells on how the denomination in fifteenths arises, tracking the single unit taken from 16 as it passes to d and rejoins the friction to restore 16/15.
On this page
Two proofs that the calculation stands
Divide the friction by the number into which the counterweight arm is split; if the result equals the counterweight of that friction, the operation was good. A second test requires the result to stand in the same proportion to the friction as the friction arm b c e stands to the counterweight arm b a, here subquadruple, confirming the calculation.
Friction is always a quarter of the rubbed weight
Leonardo restates that the friction is always a quarter of the rubbed weight: the friction d e of 16/15 is a quarter of the 64/15 at b f. The 15 at a is merely the divisor fixing the denomination in fifteenths, and could equally have stood for whole numbers, halves, thirds, or 15 times 2/3.
Tracking the unit taken from sixteen
The one taken from 16, leaving 15 in a, is placed at d and named 1/15; rejoined to the pole's friction it restores 16/15. Leonardo generalises this bookkeeping of undoing and remaking the divisor into a rule that holds for all weights, fractions as well as whole numbers.
Marginal transmutation of the numbers
A small marginal figure labelled 12, with 3 at a and 3 at b, shows that when the one joined to the 3 at a is instead joined to the 3 at b, the 4 that was at a transmutes and passes to b. Leonardo notes the same holds for all the numbers.
