h-i g-K f; d c-b-e a; d-c-b-e a
Here the portions are equal around the right triangle.
Here one has to consider by how much the portion c d e has grown beyond the portion h i K and beyond the portion h g f, more than its due. It is manifest that it has incorporated half the right triangle and about 3/4 of the opposite portion.

e – f – p a – d – g b

If the semicircle c f g is worth the 2 other semicircles a d c and a e q (as is proved by means of the right triangle c a g), it is necessary that the right triangle c a g be worth the 2 other right triangles a b c and a q g. And if the greater right triangle is worth the 2 lunules (as is proved), the 2 lesser right triangles, which are equal to that greater one, are also equal to the said two lunules.
What has been said up to here cannot be denied; but by this it has not been concluded that the lesser right triangle is the squaring of its lesser lunule, nor the middle right triangle [the squaring] of its middle lunule, since that lesser right triangle is much less than its lunule, and the middle right triangle is greater than its lunule, its lesser side being in the eighth part of the circumference of that circle in which it is figured.

But if you make the lesser right triangle proportioned to its lesser lunule as the middle one is to the middle lunule, then, that lesser right triangle being subtracted from the greater right triangle, the remainder of that greater one will be equal to the middle right triangle, which was greater than its lunule; and thus that greater one, which exceeded its lunule by as much as the lesser was surpassed by its lunule, will be diminished.
But here it will be said that the lesser right triangle too, grown according to the right triangle of the middle lunule, will itself still be greater than the lesser lunule. — (it continues following the line traced by Leonardo)
Therefore we will make the lesser portion and the middle one by the rule of Zenophon, and by this to the lesser one another lunule will be detached on the inside, and to the middle one another lunule will be added, which, squaring it and giving it to the greater right triangle, one will see the true end; because, the greater right triangle being first divided in the same proportion that the middle semicircles have among themselves, I will add the lesser quadrature to the lesser part of the greater right triangle, that is, within the division, so that thus the greater part of that right triangle will be diminished and made proportional to the lesser. Thus we shall always have the true squaring of those lunules.

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