General rules of the balance
Finding an unknown weight or arm, and placing resisting weights on the opposite arm
A cascade of graduated balances hung one from another, their beams carrying numbered weights, illustrates a set of general rules. The first rule finds an unknown second weight (or arm) from three known quantities by multiplying the degrees of the first weight by those of its arm and dividing by the degrees of the opposite arm. A second and third rule extend this to placing two resisting weights on the opposite arm, either at known sites with unknown weights or with known weights at unknown sites, defining the 'arm' as measured from the pole to the cord's contact. A worked example hangs 2 degrees of weight on a 2-degree arm and, by subsesquialtera proportion, finds the opposite arm length of 4/3 for a 3-degree weight.
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Cascade of graduated balances carrying weights
A tree of balances is drawn at the upper right, each graduated beam suspended from the one above and loaded with numbered weights hung on cords. The lettered figures a through e set out the arrangement of arms and loads that the accompanying rules address.
General rule for an unknown weight or arm
Given the first weight, the degrees of the arm that sustains it, and the second arm, the unknown second weight is found by multiplying the degrees of the first weight by those of its arm and dividing by the degrees of the second arm. Likewise, knowing the first weight, its arm and a third weight, one finds the unknown arm by the same multiplication and division.
Resisting weights on the opposite arm
To resist a weight hung on one arm, multiply its degrees by the degrees of its arm and divide by the degrees of the opposite arm to get the resisting weight, the arm being measured from the pole to the cord's contact. Further rules divide the single weight in the mind to place two unknown weights at two known sites, or two known weights at two unknown sites.
Worked example: subsesquialtera arm of 4/3
Hanging 2 degrees of gravity on an arm 2 degrees long on one side of the pole, Leonardo seeks the arm length on the far side that lets 3 degrees of weight resist it. He gives the arm to the first arm the same proportion the first weight has to the second (subsesquialtera): dividing, 2 times 3 is 6 (all thirds), and 2/3 of 6 is 4/3, so 4 thirds of arm length hold the 3 degrees of weight.
