On motion.

The weight increases, the more a rises to c.

c - a n 11 m b - permanent - is 11 mobile and is worth 10 - 9 d - S - 10 4 - f g

That proportion which the space n m has with the space n b, such the weight descended at d has with the weight that such d had at the site b. It follows that, n m being the ten elevenths of n b, the weight descended at d is nine tenths of the weight it had at the height b.

The pipe n f is 9 pounds, n b the permanent channel is 11 braccia, n d is 11 braccia, but it is 10, because the site where the weight d finds itself under m is worth 10 of the line n m, and the weight S is 10, which stops in the balance c n d against 1 at d, because c n, arm of the balance, is similar to the arm n a, and the arm n a goes 10 times into the arm n m, which is worth the arm n d.

Therefore the motion of the balance n c d will remain 4 braccia high from the ground with the extreme lowness of its counterweight, which is one; which one d has such proportion with ten, the counterweight S, as a n, arm of the balance, has with n m, its opposite arm. Therefore the motion has become immobile until the heavy d is annulled. Then it will rise to the first site b, where by means of S it will regain its lost forces, and again it will descend to the site d, etc.

The water d will pour out so much the nearer to b, as it is of lesser weight. But if you wish it to remain of the first weight, increase the thickness of the pipe, so that so much more water rises to b as d makes a smaller descent, and thus you will lift the water to any height.