Squaring the Circle and Circling the Square
Octagons in concentric circles turned into equal rectilinear figures; small marginal sketches
Written with the sheet turned upside-down, the page opens with the twin problems "Given a circle, make a square equal to it" and its converse. Leonardo inscribes two octagons in concentric circles and works to make two unequal, irrational rectilinear triangles equal by taking from one and giving to the other, arguing that a figure's "full" can be made equal to its "void." Turning the sheet back, he marks a passage "Good" and reduces the pieces into a parallelogram to note what fraction of its circle a square is, closing with the lune (falcate): if he squares the lune o he squares the equal portion n. Small faint marginal sketches of a rearing animal and a horse-and-rider also appear at the right, not covered by the transcription.
On this page
The twin problem: square the circle, circle the square
At the top (with the sheet inverted) Leonardo states the paired tasks: given a circle, make a square equal to that circle; and given a square, make a circle equal to that square.
Two octagons in concentric circles made equal
He has two rectilinear triangles, unequal and irrational, and makes them equal by taking from one and giving to the other, found in a b c and c d e. The figure has quadrature because its 8 half-portions, removed outside, are rendered inside as 8 whole portions of the same value, leaving only the interposed fillings to be equalized among the 8 parts.
The full made equal to the void
He asserts that the "full" can be made equal to the "void" — that from which portions are neither taken nor rendered. Making the base of triangle c d e just wide enough to enter exactly the space a b c yields a six-sided figure, within and without, equal to the circle within and without.
"Good": reducing the pieces into a parallelogram
With the sheet turned to normal, he notes "Good": take d r c as it is and put it into the space b c a, untroubled by the space since that piece carries a portion with it. Then reduce the whole quantity into the parallelogram o b r a, aim its face at the centre of the circle, do the same on the opposite side, and note what fraction of its circle the square is.
Squaring the lune squares the portion
A portion divided into lunes (falcate) closes the reasoning: if he gives the quadrature of the lune o, he gives the quadrature of the portion n, which is worth as much as o.
Marginal sketches of an animal and a rider
At the right edge, beside the geometry, are two small, faint pen sketches not accounted for in the transcription: a rearing horned animal above, and a mounted horse-and-rider below. They read as rapid marginal doodles rather than finished studies.
