a b, m f n, 4 7, t, S, r v, x, z q, p, y l, K

When r descends, l rises and strikes at the middle of the shaft S z; so that if S weighs one pound, at l, being struck at the middle of the shaft, it would come to 2 pounds. But because the perpendicular S q diminishes the weight S by half, therefore the 2 pounds of S come back to one pound; and the power of the weight r, when it has descended to x, will weigh 11/12 of its weight, and upon that weight is added the percussion, so that by this S will descend at the 2nd percussion. Now consider whether in such percussion it makes the sixth part of the wheel turn; if not, it is not valid.

Look above and take the pole b as the centre of gravity of the weights attached to the wheel. And if you wish to know by how much the weight n exceeds the weight m, know for yourself that if you added 3 to m you would then have 7 in m and 7 in n; the pole a of the balance would stand exactly and equally in the middle.

Now here it is almost to be doubted whether the blow of the fall of r and S has the power to turn the sixth of the wheel along with itself; and doing so, t v would then remain in the place of r S and would make the 2nd percussion, and thus it seems that successively, one after another, it ought to continue so far that the wheel, or rather the poles, would wear out.

The pole being at f, and 4 and 7 being equally distant, attached to that pole f, the 4 cannot discharge or lighten of 7 anything but itself, that is 4. Hence we shall say the 7 weighs no more than 3, so that, placing upon 4 another 3, you will then make 7 on this side of the pole and 7 on the other; and the arms of the balance being equal, the said attached weights will still show themselves equal.

Proof.

When r has descended as far as x, then its counter-lever l will touch, or rather strike, upon the shaft of S a little higher than the middle; and because the descent of r, arriving at x, has recovered 11/12 of its natural weight (by the 5th of my theory), and moreover the blow has arrived at such a site that it moves itself 3 times in the motion of the eighth of its circle, without doubt the percussion of l makes S collapse and creates the 2nd percussion.

I remind you that all the weights that have the curved counter-lever, like r, must weigh as much more as their said counter-lever weighs; otherwise it would not raise the weight S.